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25 gram saturated solution of potassium nitrate at 95 C is cooled down to 55 C then how much gram of crystals of potassium nitrate will be separated if the solubility of potassium nitrate at 95 c is 100 and 55 C is 25 correspondingly ​

Sagot :

onyebuchinnaji

The mass of  potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.

The given parameters:

  • Mass of KNO₃ = 25 g
  • Initial temperature = 95 ⁰C
  • Final temperature = 55 ⁰C
  • Solubility at 95 ⁰C = 100 M
  • Solubility at 55 ⁰C = 25 M

The mass of KNO₃ at 95 ⁰C is calculated as follows;

[tex]m = \frac{25\ g \times 100\ g}{100\ g} \\\\m = 25 \ g[/tex]

mass of water = 100 g - 25 g = 75 g

The mass of KNO₃ at 55 ⁰C is calculated as follows;

[tex]m = \frac{75 \ g \times 25 \ g}{100 \ g} \\\\m = 18.75 \ g[/tex]

The mass of  potassium nitrate (KNO₃) crystals that will be separated is calculated as;

[tex]m= 25\ g \ - \ 18.75 \ g\\\\m = 6.25 \ g[/tex]

Thus, the mass of  potassium nitrate (KNO₃) crystals that will be separated is calculated as 6.25 g.

Learn more about saturated solution and temperature here: https://brainly.com/question/4529762

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