Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

. There are 11 boys and 5 girls that tried out to
sing a duet in a chorus concert. If the
director must choose two, what is the
probability that both students chosen are
boys?

Sagot :

facundo3141592

We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458

If we assume that the selection is totally random, then all the students have the same probability of being chosen.

This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:

P = 11/16

For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).

Q = 10/15

The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:

Probability = P*Q = (11/16)*(10/15) = 0.458

So the probability that both students chosen for the duet are boys is 0.458

If you want to learn more, you can read:

https://brainly.com/question/1349408

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.