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The vertical and horizontal components of the velocity of a golf ball after being struck by a club are 4.0 m s1 and 5.0 m s respectively. Determine the magnitude and direction of the velocity of the golf ball. A 6.30 m s-1 B 6.35 m s-1 C 6.40 m s-1 D 6.45 m 5-1​

The Vertical And Horizontal Components Of The Velocity Of A Golf Ball After Being Struck By A Club Are 40 M S1 And 50 M S Respectively Determine The Magnitude A class=

Sagot :

The magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

The given parameters:

  • Vertical component of the velocity, [tex]v_y = 4 \ m/s[/tex]
  • Horizontal component of the velocity, [tex]v_x = 5 \ m/s[/tex]

The magnitude of the resultant velocity of the golf ball is calculated as follows;

[tex]v= \sqrt{v_y^2 + v_x^2} \\\\v = \sqrt{4^2 + 5^2} \\\\v = 6.4 \ m/s[/tex]

The direction of the golf ball's velocity is calculated as follows;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{4}{5} )\\\\\theta = 38.7 \ ^0[/tex]

Thus, the magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

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