At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The vertical and horizontal components of the velocity of a golf ball after being struck by a club are 4.0 m s1 and 5.0 m s respectively. Determine the magnitude and direction of the velocity of the golf ball. A 6.30 m s-1 B 6.35 m s-1 C 6.40 m s-1 D 6.45 m 5-1​

The Vertical And Horizontal Components Of The Velocity Of A Golf Ball After Being Struck By A Club Are 40 M S1 And 50 M S Respectively Determine The Magnitude A class=

Sagot :

The magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

The given parameters:

  • Vertical component of the velocity, [tex]v_y = 4 \ m/s[/tex]
  • Horizontal component of the velocity, [tex]v_x = 5 \ m/s[/tex]

The magnitude of the resultant velocity of the golf ball is calculated as follows;

[tex]v= \sqrt{v_y^2 + v_x^2} \\\\v = \sqrt{4^2 + 5^2} \\\\v = 6.4 \ m/s[/tex]

The direction of the golf ball's velocity is calculated as follows;

[tex]\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{4}{5} )\\\\\theta = 38.7 \ ^0[/tex]

Thus, the magnitude and direction of the velocity of the  golf ball is 6.4 m/s at 38.7⁰.

Learn more about magnitude and direction of velocity here: https://brainly.com/question/2456181

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.