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log x √x + log √c c² = ?
[tex] log_{x}\sqrt{x} + log_{ \sqrt{c} } {c}^{2} = \\ [/tex]
please help me!!!!?;​

Sagot :

SalmonWorldTopper

Given that

log √x (x) + log c² (c)

⇛ log x^1/2 (x) + log c² (c)

We know that

log a^m (b^n) = m/n log a (b)

⇛ 1/2 log x (x) + 2 log c (c)

We know that

log a ( a) = 1

⇛ (1/2)(1) + 2(1)

⇛ (1/2)+2

⇛ (1+4)/2

⇛ 5/2

Answer:- log √x (x) + log c² (c) = 5/2

[(x) ,(c) , (a) represents the bases ]

Additional comment:

  • (a+b)(a-b) = a²-b²
  • log a^m (b^n) = m/n log a (b)
  • log a ( a) = 1

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