Line c passes through points (9, 10) and (1, 3). Line d is perpendicular to c. What is the slope
of line d?

Question

07-12-2021
Mathematics

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Line c passes through points (9, 10) and (1, 3). Line d is perpendicular to c. What is the slope
of line d?

Sagot :

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cinderofsoulsss cinderofsoulsss · Answer 1 · 2021-12-07T02:46:38-05:00

Answer:

-8/7

Step-by-step explanation:

First, find the slope of line c.

(x1, y1) = (9, 10)

(x2, y2) = (1, 3)

The slope formula is:

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Solve for the slope using the given values:

[tex]m=\frac{3-10}{1-9}\\\\m=\frac{-7}{-8}\\\\m=\frac{7}{8}[/tex]

The slope of line c is 7/8. To find the slope perpendicular to it, you need to find the negative reciprocal of that number. An example of that would be 2 and -1/2. Basically, flip the fraction and the +/-.

In this case, the negative reciprocal of 7/8 is -8/7. The image below doesn't account for the y-intercept, but it does show that the slopes are perpendicular.

jimrgrant1 jimrgrant1 · Answer 2 · 2021-12-07T02:47:29-05:00

Answer:

slope = - [tex]\frac{8}{7}[/tex]

Step-by-step explanation:

Calculate the slope m of line c using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (9, 10 ) and (x₂, y₂ ) = (1, 3 )

m = [tex]\frac{3-10}{1-9}[/tex] = [tex]\frac{-7}{-8}[/tex] = [tex]\frac{7}{8}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{7}{8} }[/tex] = - [tex]\frac{8}{7}[/tex] ← slope of line d

Sagot :

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