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Sagot :

Answer:

y = - [tex]\frac{2}{5}[/tex] (x - 5)² + 7

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (5, 7 ) , then

y = a(x - 5)² + 7

To find a substitute (10, - 3 ) into the equation

- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )

- 10 = 5²a = 25a ( divide both sides by 25 )

[tex]\frac{-10}{25}[/tex] = a , that is

a = - [tex]\frac{2}{5}[/tex]

y = - [tex]\frac{2}{5}[/tex] (x - 5)² + 7 ← in vertex form