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what is the answer of solve the following equations and verify your answer ​ ​

What Is The Answer Of Solve The Following Equations And Verify Your Answer class=

Sagot :

AadhPrit

Answer:

Solution !!

[tex] \implies{\sf{ \dfrac{p + 7}{p - 6} = \dfrac{1}{3}}}[/tex]

By cross multiplication :

[tex] \implies{\sf{ {3(p + 7)} = 1{(p - 6)} }}[/tex]

[tex]\implies{\sf{3p + 27 = p - 6 }}[/tex]

[tex]\implies{\sf{3p - p = - 6 - 21}}[/tex]

[tex]\implies{\sf{2p = - 27}}[/tex]

[tex]\implies{\sf{\underline{\underline{\red{p = \dfrac{ - 27}{2}}}}}}[/tex]

Hence, the value of p is -27/2

[tex]\begin{gathered}\end{gathered}[/tex]

Verification !!

[tex] \implies{\sf{ \dfrac{p + 7}{p - 6} = \dfrac{1}{3}}}[/tex]

Substituting the value of (p = -27/2)

[tex] \implies{\sf{ \dfrac{ \dfrac{ - 27}{2} + 7}{ \dfrac{ - 27}{2} - 6} = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{ \dfrac{ - 27 + 14}{2}}{ \dfrac{ - 27 - 12}{2} } = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{ \dfrac{ - 13}{2}}{ \dfrac{ - 39}{2} } = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{ - 13}{2} \times \dfrac{2}{ - 39} = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{ - 13}{\cancel{2}} \times \dfrac{\cancel{2}}{ - 39} = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{ - 13}{ - 39} = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \cancel{\dfrac{ - 13}{ - 39}} = \dfrac{1}{3}}}[/tex]

[tex] \implies{\sf{ \dfrac{1}{3} = \dfrac{1}{3}}}[/tex]

[tex]\implies{\sf{\underline{\underline{\red{LHS = RHS}}}}}[/tex]

Hence Verified!

[tex]\underline{\rule{220pt}{3pt}}[/tex]

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