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A bag of mixed nuts has 14 almonds, 12 cashews, and 18 peanuts. If one nut is selected, what is the probability that a peanut is chosen?

Provide the answer as a simplified fraction.

Sagot :

noahscats11

18 / 44 = 9 / 22

There are 44 nuts in the bag, and 18 of them are peanuts. If you simplify the fraction, you get 9/22 chance of getting a peanut.

Answer:

9 / 22

Step-by-step explanation:

combine 14, 12, and 18

=44

then, divide 18 by 44

then you get 9 / 22

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