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You are thrown 4 fastballs and you must hit them in a fair zone to count.
If you hit al 4 in a fair zone, you win the big prize
If you hit 3 or 2 in a fair zone, you win a medium size prize
If you hit 1 in the fair zone, you get the small prize
If you hit zero, you are not a winner and receive nothing
Hint Create a tree diagram to help calculate the probabilities.
What is the probability you will win the big prize?
O 1/5
O 3/32
none of the above
2/9
1/16

Sagot :

Using the binomial distribution, it is found that there is a [tex]\mathbf{\frac{1}{16}}[/tex] probability you will win the big prize.

For each ball, there are only two possible outcomes, either it is hit or it is not. The probability of hitting a ball is independent of any other ball, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 4 balls are thrown, hence [tex]n = 4[/tex]
  • 0.5 probability of hitting each of them, hence [tex]p = \frac{1}{2}[/tex]

You win the big prize if you hit 4 balls, hence, the probability is P(X = 4).

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{4,4}.\left(\frac{1}{2}\right)^{4}.\left(\frac{1}{2}\right)^{0} = \frac{1}{16}[/tex]

[tex]\mathbf{\frac{1}{16}}[/tex] probability you will win the big prize.

A similar problem is given at https://brainly.com/question/24863377

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