Answered

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1) What is the equation of the line that passes through the point (-2,1) and has a slope of
-5/2?

Sagot :

ayobami2204

Answer:

y=(-5/2)x-4

Step-by-step explanation:

Step 1: Define the equation of a line.

Equation of a line is written in the form y=ax+b where a is the slope and b is the y-intercept.

Step 2: Write the given parameters

(x1,y1)=(-2,1)

m=-5/2

Using the formula y-y1=m(x-x1)

y-1=-5/2(x-(-2))

y-1=-5/2(x+2)

y-1=(-5x-10)/2

By cross multiplication,

2(y-1)=-5x-10

2y-2=-5x-10

2y=-5x-10+2

2y=-5x-8

y=(-5x-8)/2

y=(-5/2)x-4

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