coralinejones691
Answered

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what is an equation in slope-intercept form for the line (-5, 2) and (5,-3)?​

Sagot :

Answer:

y = [tex]-\frac{1}{2} x[/tex] [tex]-\frac{1}{2}[/tex]

Step-by-step explanation:

solved using point-slope form

points given: (-5, 2) and (5, -3)

slope: [tex]\frac{-3-2}{5-(-5)} =\frac{-5}{10} =-\frac{1}{2}[/tex]

y = [tex]-\frac{1}{2}[/tex] x + b

insert x- and y- values of (-5, 2) and solve for b

2 = [tex]-\frac{1}{2}[/tex] (-5) + b

2 = 2.5 + b

subtract 2.5 from both sides

2 - 2.5 = 2.5 + b - 2.5

-0.5 = b

insert b- value

y = [tex]-\frac{1}{2} x[/tex] [tex]-\frac{1}{2}[/tex]

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