Answered

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In the standard (x, y) coordinate plane, what is the
distance between the origin and the point (,5 –12)

Sagot :

Paounn

Answer:

13

Step-by-step explanation:

You simply apply the distance formula:

[tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2} =\sqrt{(5-0)^2+(-12-0)^2} = \sqrt{25+144}=\sqrt{169}=13[/tex]

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