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$14,038 is invested, part at 14% and the rest at 12%. If the interest earned from the amount invested at 14% exceeds the interest earned from the amount invested at 12% by $984.34, how much is invested at each rate? (Round to two decimal places if necessary.)

Sagot :

thomasa936

Answer:

492.99

Step-by-step explanation: x = amount invested at 12%

y = amount invested at 9%

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x + y = 20287

0.12x = 0.09y + 492.99

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put the system of linear equations into standard form

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x + y = 20287

0.12x - 0.09y = 492.99

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