Answered

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Two negative integers have a sum of -18 and a
product of 80. What are the integers?
Separate the answers with a coma.

Sagot :

zarampa

Answer:

-10, -8

Step-by-step explanation:

a + b = -18

a * b = 80

Solve:

from the first eq.

a = 18 - b

replacing this value in the secon eq.

(18-b)*b = 80

18*b + b*-b = 80

-b² + 18b = 80

-b² + 18b - 80 = 0

b = {-18±√((18)² - (4*-1*-80))] /(2*-1)

b = {-18±√(324.320)} / -2

b = {-18±√4} / -2

b = {-18±2} / -2

b₁ = {-18-2} / -2 = -20/-2 = 10

b₂ = {-18+2} / -2 = -16/-2 = 8

The two number must be negatives, so the numbers are:

-10 and -8

Check:

-10 + (-8) = -10 - 8 = -18

-10*-8 = 80

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