destinygreer49
Answered

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What is the angle, in degrees, when the coordinate is [tex](-\sqrt{2} /2), \sqrt{2} /2)[/tex] ? Pls help thanks

Sagot :

Answer:

135°

Step-by-step explanation:

seg AB=seg OB

tan ∠AOB = 1

∠AOB = 45°

∠AOC = 135°

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