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Sagot :

Answer:

A. [tex]-\frac{1}{9}[/tex]

Step-by-step explanation:

-([tex]3^-^5[/tex])([tex]3^3[/tex]) = [tex]-\frac{1}{9}[/tex]

please let me know if I am wrong.

hope this helped.

12651241

Answer:

A

Step-by-step explanation:

[tex]-\left(3^{-5}\right)\left(3^3\right)[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}[/tex]

[tex]3^{-5}\cdot \:3^3=3^{-5+3}[/tex]

= [tex]-3^{-5}\cdot \:3^3[/tex]

[tex]\mathrm{Add/Subtract\:the\:numbers:}\:-5+3=-2[/tex]

[tex]=-3^{-2}[/tex]

= [tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}[/tex]

[tex]3^{-2}=\frac{1}{3^2}[/tex]

= [tex]=-\frac{1}{3^2}[/tex]

[tex]3^2=9[/tex]

= [tex]=-\frac{1}{9}[/tex]

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