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In ΔABC, \overline{AC} AC is extended through point C to point D, \text{m}\angle BCD = (9x-1)^{\circ}m∠BCD=(9x−1) ∘ , \text{m}\angle ABC = (3x+18)^{\circ}m∠ABC=(3x+18) ∘ , and \text{m}\angle CAB = (3x-4)^{\circ}m∠CAB=(3x−4) ∘ . Find \text{m}\angle CAB.m∠CAB.

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Answer:

I cant tell what you're asking the question is all weird

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