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Ethanol (C2H5OH) reacts with oxygen gas in a combustion reaction. How many liters of carbon dioxide gas are produced at STP when 375 mL of a 75.0% ethanol solution by mass with a density of 1.22 g/mL reacts with excess oxygen?

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The volume of carbon dioxide produced when 375 mL of a 75.0% ethanol solution by mass with a density of 1.22 g/mL reacts with excess oxygen is  667.52 L.

We are told in the question that the solution contains 75.0% ethanol solution by mass.

Hence;

Density of solution = mass/volume

mass = Density × volume = 1.22 g/mL × 375 mL = 457.5 g

Mass% = mass of solute/ mass of solution × 100

Mass of solute = x

Mass of solution = 457.5 g

Mass percent = 75.0%

Substituting values;

75 = x/457.5 + x × 100

75/100 = x/457.5 + x

0.75(457.5 + x) = x

343.125 + 0.75x = x

343.125  = x -  0.75x

x = 343.125/0.25

x = 1372.5 g

The equation of the reaction is;

C2H6O(l) + 3O2(g) → 2CO2(g) + 3H2O(l)

Number of moles of ethanol =  1372.5 g/46 g/mol = 29.8 moles

From the reaction equation;

2 moles of ethanol produces 2 moles of carbon dioxide

29.8 moles of ethanol also produces 29.8 moles of carbon dioxide

If 1 mole of carbon dioxide occupies 22.4 L

29.8 moles of carbon dioxide occupies 29.8 moles × 22.4 L/ 1 mole

= 667.52 L

Learn more: https://brainly.com/question/17638582

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