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A special machine is used at a construction site to dig holes. A hole is dug to a depth of 4.75 feet when the machine hits rock. The progress slows to 3/5 feet per hour of digging. The depth of the hole must be at least 12 1/2 feet by the end of the day to stay on schedule. What is the minimum amount of time the machine must continue at its present rate to complete the hole on schedule? Select from the drop-down menus to correctly complete the statement.

HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS A Special Machine Is Used At A Construction Site To Dig Holes A Hole Is Dug To A Depth Of 475 Feet When class=
HELP ASAP PLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLSPLS A Special Machine Is Used At A Construction Site To Dig Holes A Hole Is Dug To A Depth Of 475 Feet When class=

Sagot :

EbonyTheNB

Answer: 12 h ; 45 m

Step-by-step explanation:

*Important: From what I can see in this image, this appears to be a test. If this is the case, please do not cheat. In any case, here is the explanation.

What we know:

  • Progress has been made to 4.75
  • Rate of digging is 3/5 mph
  • Depth must be at least 12 1/2
  • We need to find the minimum amount of time the machine works

How to solve:

By setting up an algebraic equation, we can solve this.

Process:

  • Set up equation                            4.75 + 3/5x = 12 1/2
  • Convert                                          19/4 + 3/5x = 12 1/2

                                                                95/20 + 12/20x = 250/20

  • Subtract                                           -95/20                 -95/20

                                                                               12/20x= 155/20

  • Isolate x via division                                       /(12/20) /(12/20)
  • +Simplify                                                          

                                                                                         x= 12 11/20

  • Convert                                                                    12 h 33 m

Solution: 12 ; 45

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