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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 18 feet and a height of 15 feet. Container B has a diameter of 16 feet and a height of 18 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full.

To the nearest tenth, what is the percent of Container A that is full after the pumping is complete?

Sagot :

obinnafavour66

Answer:

5.2%

Step-by-step explanation:

Volume of cylinder= πr²h

In Container A,

D= 18ft, r=18/2=9ft, h=15ft

volume= 22/7 × 9² × 15

= 26730/7 cubic ft.

In Container B,

D=16ft, r= 16/2=8ft, h=18ft

volume= 22/7 × 8² × 18

= 25344/7 cubic ft.

percent of amount of water left in Container A= percent of container A that is full after pumping

Amount of water left in Container A,

26730/7 - 25344/7 = 1386/7

Therefore, % of container A that is full= 1386/7 ÷ 26730/7 × 100

(1386×7×100)/(7×26730)= 5.185

To the nearest tenth= 5.2%

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