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Sagot :
- A rectangle has a perimeter of 44 inches and an area of 72 square inches.
- Perimeter = 44 inches, area = 72 square inches.
- Let the length and breadth be l and b respectively.
- We know, perimeter of a rectangle = 2(l + b)
- Therefore,
- 2(l + b) = 44
or, l + b = 22
or, b = 22 - l ...(i)
- We know, area of a rectangle = lb
- Therefore,
- lb = 72
- Putting (i) in b, we get
- l(22 - l) = 72
or, 22l - l^2 -72 = 0
or, l^2 - 22l + 72 = 0
or, l^2 - 4l - 18l + 72 = 0
or, l(l - 4) - 18(l - 4) = 0
or, (l - 4)(l - 18) = 0
or, l = 4 or l = 18
- Therefore, if the length is 4 inches, then the breadth is (22-4) inches, i.e., 18 inches.
- And if the length is 18 inches, then the breadth is (22-18) inches, i.e., 4 inches.
Answer:
B) 4 inches and 18 inches.
Hope you could get an idea from here.
Doubt clarification - use comment section.
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