Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
- A rectangle has a perimeter of 44 inches and an area of 72 square inches.
- Perimeter = 44 inches, area = 72 square inches.
- Let the length and breadth be l and b respectively.
- We know, perimeter of a rectangle = 2(l + b)
- Therefore,
- 2(l + b) = 44
or, l + b = 22
or, b = 22 - l ...(i)
- We know, area of a rectangle = lb
- Therefore,
- lb = 72
- Putting (i) in b, we get
- l(22 - l) = 72
or, 22l - l^2 -72 = 0
or, l^2 - 22l + 72 = 0
or, l^2 - 4l - 18l + 72 = 0
or, l(l - 4) - 18(l - 4) = 0
or, (l - 4)(l - 18) = 0
or, l = 4 or l = 18
- Therefore, if the length is 4 inches, then the breadth is (22-4) inches, i.e., 18 inches.
- And if the length is 18 inches, then the breadth is (22-18) inches, i.e., 4 inches.
Answer:
B) 4 inches and 18 inches.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
