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Simplify fully
A)
X^7 / X^3


B)
Y^5 / Y^4

Sagot :

Hi,

[tex]\frac{x^{a} }{x^{b} } =x^{a-b}[/tex]

a)

[tex]\frac{x^{7} }{x^{3} }= x^{7-3} = x^{4}[/tex]

b)

[tex]\frac{y^{5} }{y^{4} } = y^{5-4} = y^{1} = y[/tex]

;)