laraib72
Answered

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How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?
1
2
3
6

Sagot :

naǫ
[tex]2 \ KClO_3 \to 2 \ KCl + 3 \ O_2 \\ \\ n_{KClO_3}:n_{O_2}=2:3[/tex]

When 2 moles of potassium chlorate decompose, 3 moles of oxygen are produced.
Diatonic254

The answer is 3. The number in front of an element or compound in a chemical reaction usually indicated the number of moles of that compound or element. Therefore two moles of potassium chlorate is; 2KClO3

This means that there are 6 oxygen atoms ( Note: multiplied by the Avogadro's number 6.022 * 10^23). 6 oxygen atoms will form 3 oxygen molecules since an oxygen molecule is made of two (2) oxygen atoms (O2). The following balanced equation indicates this;

2KClO3 - 2KCl + 3O2


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