Answered

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Solve each equation by factoring.
12-27n^2=0

Sagot :

[tex]12-27n^2=0\ \ \ \ /-12\\\\-27n^2=-12\ \ \ \ /:(-27)\\\\n^2=\frac{-12}{-27}\\\\n^2=\frac{4}{9}\\\\n=\pm\sqrt\frac{4}{9}\\\\n=-\frac{2}{3}\ \vee\ n=\frac{2}{4}[/tex]
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