anjalee
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

4x^2 +28x -32 =0 solve this problem?

Sagot :

mariamikayla
[tex]4x^2+28x-32=0 \ \ \ |:4 \\\\ x^2+7x-8=0 \\\\ x^2+8x-x-8=0 \\\\ x(x+8)-(x+8)=0 \\\\ (x+8)(x-1)=0 \\\\ \\x+8=0 \\\\ \boxed{x=-8} \\\\\\ x-1=0 \\\\ \boxed{x=1} \\\\\\ \boxed{\boxed{S=\{-8;1 \}}}[/tex]
apologiabiology
we know that if xy=0 then x or/and y=0


4x^2+28x-32=0
factor out the 4
4(x^2+7-8)=0

factor out the x^2+7-8
we must find out what two numbers multiply to get -8 and add to get 7
the numbers are 8 and -1

so 4[(x-1)(x+8)]=0

we know that if exg 4y=0 then y=0
so
therefor
(x-1)(x+8)=0
set each to zero
x-1=0
x=1
x+8=0
x=-8

x could be 1 or -8
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.