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Sagot :
ok so the series is x,y,and z
x+y+z=42
3.2(x+y)=z
rearrange the first equation to get
z=42-x-y
3.2(x+y)=42-x-y
OR
3.2x+3.2y=42-x-y
combine the x's and y's to one side
4.2x+4.2y=42
divide everything by 4.2
x+y=10
place that into the first equation
10+z=42
subtract 10 from both sides
z=32
the other 2 terms have to be smaller by a constant multiple knowing the number 32 divides nicely by 8 and 4 we can try both of those number i started with 8 so 8times4 gives you 32 and if you divide 8 by 4 you get 2 8=y and x=2 x+y=10 those work!! hope this helps
x+y+z=42
3.2(x+y)=z
rearrange the first equation to get
z=42-x-y
3.2(x+y)=42-x-y
OR
3.2x+3.2y=42-x-y
combine the x's and y's to one side
4.2x+4.2y=42
divide everything by 4.2
x+y=10
place that into the first equation
10+z=42
subtract 10 from both sides
z=32
the other 2 terms have to be smaller by a constant multiple knowing the number 32 divides nicely by 8 and 4 we can try both of those number i started with 8 so 8times4 gives you 32 and if you divide 8 by 4 you get 2 8=y and x=2 x+y=10 those work!! hope this helps
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