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Given the equation y + 5 = −23(x − 7) what is a point on the line?

Sagot :

Answer:

(0, - [tex]\frac{1}{3}[/tex]).

Step-by-step explanation:

     First, let's simplify the equation:

[Given] y + 5 = −[tex]\frac{2}{3}[/tex](x − 7)

[Distribute] y + 5 = -[tex]\frac{2}{3}[/tex]x + [tex]\frac{14}{3}[/tex]

[Subtract 5 from both sides] y = -23x - [tex]\frac{1}{3}[/tex]

     Now, we know that the y-intercept (- [tex]\frac{1}{3}[/tex]) will be a

                    point on the graph as (0, -

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

(1, -1)

(0, -1/3)

Step-by-step explanation:

y + 5 = −2/3(x − 7)

We can use distribute property to open up the parentheses.

y + 5 = -2/3x - (-4 2/3)

Two negatives equals one positive

y + 5 = -2/3x + 4 2/3

minus 4 2/3 on both sides

y + 1/3 = -2/3x

Some possible ordered pairs can be

(1, -1)

(0, -1/3)