lvettiyadan19
Answered

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17. Oscar, Lily and Jack collect souvenir coins. Oscar has 44 more coins than Lily and 48 more coins than Jack, Oscar has 6 more coins than Lily and Jack combined. (A) (B) (C) (D) 196 166 156 146 How many coins do Oscar, Lily and Jack have altogether?​

Sagot :

Kogarashi

Answer:

166 marbles

Step-by-step explanation:

O - 44 = L

O - 48 = J

O - 6 = L + J

I want to isolate O here

O = 44 + L

Plug it in

44 + L - 6 = L + J

38 + L = L + J

38 = J

Now we know that Jack has 38.

O - 48 = J

O - 48 = 38

O = 86

Now we know Oscar has 86.

O - 44 = L

86 - 44 = L

42 = L

Lily has 42.

38 + 86 + 42 = .....166

They have 166 coins altogether - Also Happy New Year!!! :D

Answer:

b; 166 coins

Step-by-step explanation:

let o = oscar

let l = lily

let j = jack

o = l + 44

o = j + 48

o = l + j + 6

you can combine the first 2 equations together using substitution

l + 44 = j + 48

then reorder the 3rd to have l in front

-l = -o + j + 6 -->

l = o - j - 6

o - j - 6 + 44 = j + 48

then simplify the equation down

o = 2j + 10

then use the 2nd equation as substitution for o

j + 48 = 2j + 10

simplify

j = 38

finally you find o and l

38 + 48 = o --> o = 86

86 = l + 44 --> l = 42

last but not least you add them together

38 + 86 + 42 = 166

b is the correct answer

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