taranidevi12
Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Solve X.
Do help need it quickly, will rate as the brainliest!​

Solve XDo Help Need It Quickly Will Rate As The Brainliest class=

Sagot :

gmany

Answer:

[tex]\huge\boxed{x=65}[/tex]

Step-by-step explanation:

Look at the picture.

[tex]m\angle VUP=180^o-2\cdot60^o=180^o-120^o=\boxed{60^o}\\\\m\angle UPQ=360^o-2\cdot60^o=360^o-120^o=\boxed{240^o}\\\\m\angle QRM=180^o-2\cdot60^o=180^o-120^o=60^o\\\\m\angle RMQ=180^o-135^o=45^o\\\\in\ \triangle QRM:\ m\angle MQR=180^o-(60^o+45^o)=180^o-105^o=75^o\\\\m\angle PQW=360^o-(2\cdot60^o+75^o+80^o)=360^o-(120^o+155^o)\\\\=360^o-275^o=\boxed{85^o}\\\\m\angle UVW=\boxed{90^o}[/tex]

VWQPU is the pentagon. The sum of interior angles in a pentagon is equal 540°. Therefore:

[tex]x^o=540^o-(90^o+60^o+240^o+85^o)=540^o-475^o=65^o[/tex]

View image gmany
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.