Answer:
A is the answer.
Step-by-step explanation:
We have
[tex] \sqrt[3]{56 {x}^{7} {y}^{5} } [/tex]
Factor the radical by taking perfect squares of the real numbers and the exponents.
56 can be made up of perfect 8, x^7 can be made up of x^6 and y^5 can be made up of y^3. So we get
[tex] \sqrt[3]{8 {x}^{6} {y}^{3} \times \sqrt{7xy {}^{2} } } [/tex]
Take the cube root of 8x^6y^3.
Which is 2x^2y.
[tex]2 {x}^{2} y \sqrt[3]{7xy {}^{2} } [/tex]
A is the answer.
