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The level of water in a measuring cylinder rose to 90cm³ mark when a piece of stone whose mass is 10 g was dropped in the measuring cylinder. the initial volume of the water as 50 cm³ calculate the density of the rock. show working ( means show your calculations of how you solved it :] )
pleaae this is under science but it's not giving me that option so i choose chemistry

Sagot :

Answer:

o.25g/cm3

Explanation:

initial volume(V1)= 50cm3

final volume(V2)= 90cm3

volume of stone(i.e, level of water displaced)= V2 - V1

= 40cm3

mass of stone= 10g

density= mass/volume

= 10g/40cm3

= 0.25g/cm3