Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Specific heat capacity of unknown liquid is given as,
[tex]S_{liq} =7.77J/g[/tex]°[tex]C[/tex]
Explanation:
Let the mass of unknown liquid is "m"
Now when unknown liquid is mixed with water then heat given by water is equal to the heat absorbed by unknown liquid
So we have
Msliq ( 50 - 20 ) = (240 - m) (4.2)(80-50)
Now again we did the same experiment but this time the mass of unknown liquid is "m - 20"
so we have
(m-20)Sliq(52-20)=(220-m)(4.2)(80-52)
now from above two equations
m(30)/(m-20)32 = (240-m)30/(220-m)/28
Now we have
30m * 28 (220 - m) = 32 ( m- 20) * 30 ( 240 - m)
so we have
m = 84.2g
Now we have
Sliq = 240-84.2/84.2 (4.2)
Sliq = 7.77J/g°C
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.