Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

: Activity: A liquid of unknown specific heat at a temperature of 20°C wa: 80°C in a well-insulated container. The final temperature was measure combined mass of the two liquids was measured to be 240g. In a se both liquids at the same initial temperatures, 20 g less of the liquid of was poured into the same amount of water as before. This time the ec was found to be 52°C. Determine the specific heat of the liquid. The s 4187 J/Kg°C or 1 kcal/kg°C.​

Sagot :

Answer:

Specific heat capacity of unknown liquid is given as,

[tex]S_{liq} =7.77J/g[/tex]°[tex]C[/tex]

Explanation:

Let the mass of unknown liquid is "m"

Now when unknown liquid is mixed with water then heat given by water is equal to the heat absorbed by unknown liquid

So we have

Msliq ( 50 - 20 ) = (240 - m) (4.2)(80-50)

Now again we did the same experiment but this time the mass of unknown liquid is "m - 20"

so we have

(m-20)Sliq(52-20)=(220-m)(4.2)(80-52)

now from above two equations  

m(30)/(m-20)32 = (240-m)30/(220-m)/28

Now we have

30m * 28 (220 - m) = 32 ( m- 20) * 30 ( 240 - m)

so we have

m = 84.2g

Now we have

Sliq = 240-84.2/84.2 (4.2)

Sliq = 7.77J/g°C

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.