Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

: Activity: A liquid of unknown specific heat at a temperature of 20°C wa: 80°C in a well-insulated container. The final temperature was measure combined mass of the two liquids was measured to be 240g. In a se both liquids at the same initial temperatures, 20 g less of the liquid of was poured into the same amount of water as before. This time the ec was found to be 52°C. Determine the specific heat of the liquid. The s 4187 J/Kg°C or 1 kcal/kg°C.​

Sagot :

Answer:

Specific heat capacity of unknown liquid is given as,

[tex]S_{liq} =7.77J/g[/tex]°[tex]C[/tex]

Explanation:

Let the mass of unknown liquid is "m"

Now when unknown liquid is mixed with water then heat given by water is equal to the heat absorbed by unknown liquid

So we have

Msliq ( 50 - 20 ) = (240 - m) (4.2)(80-50)

Now again we did the same experiment but this time the mass of unknown liquid is "m - 20"

so we have

(m-20)Sliq(52-20)=(220-m)(4.2)(80-52)

now from above two equations  

m(30)/(m-20)32 = (240-m)30/(220-m)/28

Now we have

30m * 28 (220 - m) = 32 ( m- 20) * 30 ( 240 - m)

so we have

m = 84.2g

Now we have

Sliq = 240-84.2/84.2 (4.2)

Sliq = 7.77J/g°C

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.