meorifaust
Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Consider the equation tan(270° + 0)= 1 - sin∅/cos∅ where 0° <∅ < 360°
(a) Rewrite the equation in terms of sin ∅ only.

(b) Hence solve the equation for 0° < ∅ < 360°.​

Consider The Equation Tan270 0 1 Sincos Where 0 Lt Lt 360 A Rewrite The Equation In Terms Of Sin Only B Hence Solve The Equation For 0 Lt Lt 360 class=

Sagot :

[tex]\\ \sf\longmapsto tan(270+\theta)=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin(270+\theta)}{cos(270+\theta)}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-cos\theta}{sin\theta}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto\dfrac{sin\theta}{cos\theta} \dfrac{-cos\theta}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta-cos^2\theta}{-cos\theta sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{-2cos\theta}{-cos\theta sin\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto 2cosec\theta=1[/tex]

[tex]\\ \sf\longmapsto cosec\theta=\dfrac{1}{2}[/tex]

[tex]\\ \sf\longmapsto \theta=cosec^{-1}\left(\dfrac{1}{2}\right)[/tex]

  • theta doesn't exist
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.