meorifaust
Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Consider the equation tan(270° + 0)= 1 - sin∅/cos∅ where 0° <∅ < 360°
(a) Rewrite the equation in terms of sin ∅ only.

(b) Hence solve the equation for 0° < ∅ < 360°.​

Consider The Equation Tan270 0 1 Sincos Where 0 Lt Lt 360 A Rewrite The Equation In Terms Of Sin Only B Hence Solve The Equation For 0 Lt Lt 360 class=

Sagot :

[tex]\\ \sf\longmapsto tan(270+\theta)=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin(270+\theta)}{cos(270+\theta)}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-cos\theta}{sin\theta}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto\dfrac{sin\theta}{cos\theta} \dfrac{-cos\theta}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta-cos^2\theta}{-cos\theta sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{-2cos\theta}{-cos\theta sin\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto 2cosec\theta=1[/tex]

[tex]\\ \sf\longmapsto cosec\theta=\dfrac{1}{2}[/tex]

[tex]\\ \sf\longmapsto \theta=cosec^{-1}\left(\dfrac{1}{2}\right)[/tex]

  • theta doesn't exist
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.