meorifaust
Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Consider the equation tan(270° + 0)= 1 - sin∅/cos∅ where 0° <∅ < 360°
(a) Rewrite the equation in terms of sin ∅ only.

(b) Hence solve the equation for 0° < ∅ < 360°.​

Consider The Equation Tan270 0 1 Sincos Where 0 Lt Lt 360 A Rewrite The Equation In Terms Of Sin Only B Hence Solve The Equation For 0 Lt Lt 360 class=

Sagot :

[tex]\\ \sf\longmapsto tan(270+\theta)=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin(270+\theta)}{cos(270+\theta)}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-cos\theta}{sin\theta}=1-\dfrac{sin\theta}{cos\theta}[/tex]

[tex]\\ \sf\longmapsto\dfrac{sin\theta}{cos\theta} \dfrac{-cos\theta}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta-cos^2\theta}{-cos\theta sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto \dfrac{-2cos\theta}{-cos\theta sin\theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{sin\theta}=1[/tex]

[tex]\\ \sf\longmapsto 2cosec\theta=1[/tex]

[tex]\\ \sf\longmapsto cosec\theta=\dfrac{1}{2}[/tex]

[tex]\\ \sf\longmapsto \theta=cosec^{-1}\left(\dfrac{1}{2}\right)[/tex]

  • theta doesn't exist
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.