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g(n) = -2n -4 f(n) = 3n +1 Find g(n) *f(n)

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[tex]g(n) = - 2n - 4 \\ f(n) = 3n + 1[/tex]

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[tex]g(n) \times f(n) = ( - 2n - 4)(3n + 1) \\ => -2n ( 3n + 1 ) -4 ( 3n + 1 ) \\ = > - 6n² - 2n - 12n - 4 \\ = > - 6n² - 14n - 4 \\ = > - (16n² + 14n + 4)[/tex]

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Answer:

g(n) * f(n) = -6n² -14n - 4  

Step-by-step explanation:

Given the following function operations g(n) * f(n), where: g(n) = -2n - 4, and f(n) = 3n + 1:

We can express the product of both functions as follows:

( g · f )(n) = g(n) · f(n) = (-2n -4)(3n + 1)

Next, use the FOIL method:

( g · f )(n) = (-2n -4)(3n + 1) = -6n² -2n - 12n - 4

Combine like terms:

( g · f )(n) = -6n² -14n - 4  

Therefore, g(n) * f(n) = -6n² -14n - 4.

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