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A man observes the top of a tower of 80√3m height from 240m far from the foot of the tower, find the angle of elevation.

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Sagot :

Hrishii

Answer:

30°

Step-by-step explanation:

[tex]height \: of \: the \: tower \: (h)\: = 80 \sqrt{3} \: m \\ distance \: of \: the \: observer \: (d) = 240 \: m \\ \\ let \: \theta \: be \: the \: angle \: of \: elevation \\ \\ \therefore \: tan \theta = \frac{h}{d} \\ \\ = \frac{80 \sqrt{3} }{240} \\ \\ = \frac{ \sqrt{3} }{3} \\ \\ \therefore \: tan \theta = \frac{1}{ \sqrt{3} } \\ \\ \implies \: tan \theta = \tan \: 30 \degree \\ \\ \huge{ \red {\therefore \: \theta \: = 30 \degree}}[/tex]

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