Answer:
[tex]y + 7 = \frac{1}{3} (x - 6)[/tex]
Step-by-step explanation:
using equation y=mx+c where y is -7, x is 6 and m is 1/3
equate them in the equation to work out c
[tex]y = mx + c[/tex]
[tex]- 7 = \frac{1}{3} (6) + c[/tex]
1/3 × 6 is 2
[tex]- 7 = 2 + c[/tex]
subtract 2 on both sides to find c
[tex]- 7 - 2 = c[/tex]
[tex]c = - 9[/tex]
The equation is
[tex]y = \frac{1}{3} x - 9[/tex]
based out of the following options you have:
i would expand each equation you have and equate it in y=mx+c to see where you have the same equation as above.
It looks like the third option is correct:
writing out the third option
[tex]y + 7 = \frac{1}{3} (x - 6)[/tex]
expanding the right side my multiplying. 1/3 × x is 1/3x. 1/3 × -6 is -2
[tex]y + 7 = \frac{1}{3} x - 2[/tex]
subtract 7 on both sides so you have y on its own
[tex]y = \frac{1}{3} x - 2 - 7[/tex]
[tex]y = \frac{1}{3} x - 9[/tex]
so the third option is the same equation as y=1/3x - 9
answer:
[tex]y + 7 = \frac{1}{3} (x - 6)[/tex]
