Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
1.255 L
Explanation:
Assuming that carbon dioxide acts as an ideal gas given the following conditions, using the ideal gas equation shown below
[tex]pV \ = \ nRT[/tex],
and since
[tex]n \ = \ \displaystyle\frac{m}{M_{r}}[/tex],
rewriting and rearranging the prior equation to make the variable [tex]V[/tex] the subject, yields
[tex]V \ = \ \displaystyle\frac{mRT}{pM_{r}}[/tex],
where [tex]V[/tex] is the volume occupied by the gas, [tex]m[/tex] is the mass of the gas, [tex]R[/tex] is the gas constant, [tex]T[/tex] is the temperature in Kelvins, [tex]p[/tex] is the pressure exerted by the gas and [tex]M_{r}[/tex] is the molecular weight of the gas molecule.
Therefore, plugging the given values into the rearranged equation,
[tex]V \ = \ \displaystyle\frac{(2.2 \ \text{g})(0.08314 \ \text{L} \ \text{bar} \ \text{mol}^{-1} \ \text{K}^{-1})(27 \ + \ 275) \text{K}}{(1 \ \text{bar})(12 + 2 \times16)\text{g mol}^{-1}} \\ \\ V \ = \ 1.255 \ \text{L} \quad \text{(4 s.f.)}[/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
