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Answered

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someone explain it plz​

Someone Explain It Plz class=

Sagot :

Molar mass of CO_2=44g/mol

No of moles=1.5mol

Mass of CO_2

[tex]\\ \sf\longmapsto No\:of\:moles(Molar\:mass)[/tex]

[tex]\\ \sf\longmapsto 44(1.5)[/tex]

[tex]\\ \sf\longmapsto 66g[/tex]

And

Molar mass of water=18g/mol

No of moles=2

Mass of H_2O

[tex]\\ \sf\longmapsto 2(18)=36g[/tex]

Total mass of products

[tex]\\ \sf\longmapsto 66+36=102g[/tex]

EMPIRICAL FORMULA:-CH_2O_3

Empirical formula mass:-

[tex]\\ \sf\longmapsto 12+2(1)+3(16)=12+2+48=62g[/tex]

We need n now

[tex]\\ \sf\longmapsto n=\dfrac{Molecular\:mass\:of\; products}{Empirical\: formula\:mass}[/tex]

[tex]\\ \sf\longmapsto n=\dfrac{102}{62}[/tex]

[tex]\\ \sf\longmapsto n=1.64\approx 2[/tex]

Now

[tex]\\ \sf\longmapsto Molecular\: formula=n(Empirical\: formula)[/tex]

[tex]\\ \sf\longmapsto 2(CH_2O_3)[/tex]

[tex]\\ \sf\longmapsto C_2H_4O_6[/tex]

It's Ethene Oxide .

Answer is Ethene(C_2H_4)

Option B is correct

Done

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