coralmbsullivan
Answered

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Ik a) but I need help with b)

Ik A But I Need Help With B class=

Sagot :

Answer:

[tex]{ \rm{ {( \frac{1}{ \sqrt{3} }) }^{7} }} \\ [/tex]

• First rationalise the denominator:

[tex] = { \rm{ {( \frac{1 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} }) }^{7} }} \\ \\ = { \rm{ {( \frac{ \sqrt{3} }{3}) }^{7} }}[/tex]

• Open the bracket, by distributing the power to both the numerator and denominator:

[tex] = { \rm{ \frac{( \sqrt{3} ) {}^{6} \times \sqrt{3} }{ {3}^{7} } }} \\ \\ = { \rm{ \frac{27 \sqrt{3} }{2187} }} \\ \\ = { \rm{ \frac{ \sqrt{3} }{81} }}[/tex]

b is 3 and c is 81

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