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what is the inverse function for h(x) = [tex]\sqrt{x+7} -1[/tex]

Sagot :

Step-by-step explanation:

[tex]y = \sqrt{x + 7} - 1[/tex]

Replace x and y.

[tex]x = \sqrt{y + 7} - 1[/tex]

Solve for y.

[tex]x + 1 = \sqrt{y + 7} [/tex]

Square both sides.

[tex](x + 1) {}^{2} = y + 7[/tex]

[tex](x + 1) {}^{2} - 7 = y[/tex]

This is the inverse function or you can also say

[tex] {x}^{2} + 2x - 6 = y[/tex]

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