Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
let's recall that d = rt, or namely distance = rate * time, the time being in a unit "in the rate".
Train A is moving North with 76m/h, Train B is going South at 44 m/h, both taking off in opposite direction at the same time, hmmmm so at some point the distance covered by both will be 22 miles, let's say that happens at the "h" hour.
If at "h" hour A has covered say distance "d" miles, then we can say that B has covered "22 - d" miles or namely the slack from 22, let's make a table with all that
[tex]\begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ A&d&76&h\\ B&22-d&44&h \end{array}\qquad \implies \qquad \begin{cases} d = 76h\\ 22-d=44h \end{cases}[/tex]
[tex]\stackrel{\textit{substituting on the 2nd equation}}{22-(76h)=44h}\implies 22=120h\implies \cfrac{22}{120}=h\implies \cfrac{11}{60}=\underset{hrs}{h} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{converting the hours to minutes}}{\cfrac{11}{60}\cdot 60\implies \underset{mins}{11}}~\hfill[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
