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Sagot :
Solving the algebraic equations given, the missing numbers in the boxes can be known as shown in the steps below.
Given the equation, ⅔(x - 1) = ⅕(2x - 3) + 1
First, apply the distribution property to open the bracket.
Thus:
⅔x - ⅔ = ⅖x - ⅗ + 1
⅔x - ⅔ = ⅖x + ⅖
- Subtract ⅖x from both sides
⅔x - ⅖x - ⅔ = ⅖
4/15x - ⅔ = ⅖
- Add ⅔ to both sides
4/15x = ⅖ + ⅔
4/15x = 16/15
- Multiply both sides by 15/4
x = 16/15 × 15/4
x = 4
Given the equation, 3c - 3 + 2(3c + 1) = - (3c + 1)
- Open the bracket using distributive property
3c - 3 + 6c + 2 = -3c - 1
- Add like terms
9c - 1 = -3c - 1
- Add 3c to both sides
9c + 3c - 1 = -1
12c - 1 = -1
- Add 1 to both sides
12c = -1 + 1
12c = 0
- Divide both sides by 12
c = 0
Learn more about algebraic equations on:
https://brainly.com/question/7784687
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