srkhundmiri
Answered

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The point (0,1) and (9,2) fall on a particular line. what is it's equation in slope intercept form?​

Sagot :

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{9}-\underset{x_1}{0}}}\implies \cfrac{1}{9}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{1}{9}}(x-\stackrel{x_1}{0})\implies \stackrel{\textit{slope-intercept form}}{y=\cfrac{1}{9}x+1}[/tex]

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