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what are the coordinates of the vertex of the parabola with the equation y=x^2+2x-3

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victoriapod

Answer: Answer is (-1,-4).

[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-3} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 2}{2(1)}~~~~ ,~~~~ -3-\cfrac{ (2)^2}{4(1)}\right)\implies \left( -1~~,~~-3-1 \right)\implies (-1~~,~~-4)[/tex]

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