devil0184
Answered

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How much work will be done by electric energy source with a P.d of 4KV that delivers a current of 1 A for 1 minute?

Sagot :

Answer:

Given that battery V = 12.0 V

Resistance R = 2.0 ohms

a ) current in the battery is I = V /R

                                                = 12.0 V / 2.0

                                                = 6.0 A

b ) charge transported in the circuit is   q = i * t  

                                                                = 6.0 A * 10 s

                                                                 = 60 C

c ) Work done on the charge by the electric field is 0 ( there is no internal resistance )

d ) work done through the resistor is w = P * t

                                                            = ( V)^2 / R * t

                                                            = ( 12.0 V )^2 / 2 *10s

                                                             = 720J

e ) Total work done is equal to work done through the resistor

                       W_total = 720 J

f ) there is no internal resistance hence  E = 0

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