Answered

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Which equation describes a line parallel
to y= 4x+ 5 through point (-2, 1)?

Sagot :

leena

Hi there!

For a line to be PARALLEL, it must contain the same slope.

The given line has a slope of 4, so we can use the point-slope formula to solve:

[tex]\large\boxed{y - y_1 = m(x - x_1)}[/tex]

y1 = y-coordinate of given point

x1 = x-coordinate of given point

m = slope

Plug in the values:

[tex]y - 1 = 4(x - (-2))\\\\y - 1 = 4(x + 2)[/tex]

Simplify:

[tex]y - 1 = 4x + 8\\\\\boxed{y = 4x + 9}[/tex]

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