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The points (9, 1) and (6, 0) Fall on a particular line. what is it's equation in slope-intercept form?​

Sagot :

Answer:

y = [tex]\frac{1}{3}[/tex]x - 2

Step-by-step explanation:

[Slope-Intercept Form] y = mx + b

-> m is the slope

-> b is the y-intercept

[Slope] Change in y divided by change in x

[tex]\frac{0-1}{6-9} =\frac{-1}{-3} =\frac{1}{3}[/tex]

[Y-Intercept] Where the line hits the y-axis

-> Plug in our slope & a point, and solve for b

y = [tex]\frac{1}{3}[/tex]x + b

1 = [tex]\frac{1}{3}[/tex](9) + b

1 = 3 + b

-2 = b

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

y = 1/3x − 2

Formula:

Slope-intercept form:  y = mx + b

Hope this helped. Happy new year! :)