Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
- (a² + b²)/a³b
Step-by-step explanation:
Simplify the given expression:
- a³b⁵/b⁴a⁶ + a⁸b⁶/b⁷a⁹
The first fraction simplifies as:
- b/a³ by cancelling a³ and b⁴
The second fraction simplifies as:
- 1/ab by cancelling a⁸ and b⁶
The sum becomes:
- b/a³ + 1/ab = Common denominator is a³b
- b²/a³b + a²/a³b = Multiply the first fraction by b, the second by a²
- (a² + b²)/a³b
Answer:
[tex]\Huge\boxed{ \bf \dfrac{ {b}^{2} + {a}^{2} }{ {a}^{3}b }} [/tex]
Step-by-step explanation:
Given expression:
[tex] \sf \longmapsto \dfrac{ {a}^{3} {b}^{5} }{b {}^{4} {a}^{6} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
Solution:
[tex] \sf \longmapsto \dfrac{ {a}^{3} {b}^{5} }{b {}^{4} {a}^{6} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
Cancel a^3 and a^6 on the left hand side of plus sign, which results to a^3.
[tex] \sf \longmapsto\dfrac{ \cancel{{a}^{3}} {b}^{5} }{b {}^{4} \cancel{{a}^{6}} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
That is,
[tex] \sf \longmapsto \dfrac{b {}^{5} }{b {}^{4} a {}^{3} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
Cancel b^5 and 5^4 on the LHS of plus sign, which results to b.
[tex]\sf \longmapsto \dfrac {\cancel{b {}^{5} }}{ \cancel{b {}^{4}} a {}^{3} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
That is,
[tex]\sf \longmapsto \dfrac{b }{ a {}^{3} } + \dfrac{ {a}^{8} {b}^{6} }{b {}^{7} a {}^{9} } [/tex]
Now cancel a^8 and a^9 on the RHS of Plus sign, which results to a.
[tex] \sf \longmapsto\dfrac{b }{ a {}^{3} } + \dfrac{ \cancel{{a}^{8}} {b}^{6} }{b {}^{7} \cancel{a {}^{9}} }[/tex]
That is,
[tex] \sf \longmapsto \: \dfrac{b }{ a {}^{3} } + \dfrac{ {b}^{6} }{b {}^{7} a {}^{} }[/tex]
Cancel b^6 and b^7 on the RHS of the Plus sign, which results to b.
[tex] \sf \longmapsto\dfrac{b }{ a {}^{3} } + \dfrac{ \cancel{ {b}^{6}} }{ \cancel{b {}^{7}} a {}^{} }[/tex]
That is,
[tex]\sf \longmapsto\dfrac{b }{ a {}^{3} } + \cfrac {1}{ {b {}^{1}} a {}^{} }[/tex]
Simply add:-
Rewrite into:
[tex] \sf \longmapsto \: \dfrac{ b {}^{} }{a {}^{3} } + \cfrac{1}{a \times b} [/tex]
Combine the numerators over LCD(a^3)
[tex] \sf \longmapsto \: \dfrac{ {b}^{2} + {a}^{2} }{ {a}^{3}b } [/tex]
Or it can also be rewritten as,
[tex] \sf \longmapsto \: \dfrac{ {a}^{2} + {b}^{2} }{ {a}^{3}b } [/tex]
________________________________
I hope this helps!
Please let me know if you have any questions
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.