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Sagot :
Answer:
Hey There!
Let's solve...
[tex] \frac{a^{3} {b}^{5} }{ {b}^{4} {a}^{6} } + \frac{ {a}^{8} {b}^{6} }{ {b}^{7} {a}^{9} } \\ \\ \\ = \frac{ {a}^{3} { \cancel{b}^{5}} }{{ \cancel{b}^{4}} {a}^{6} } \\ \\ = \frac{ {a}^{3}b }{ {a}^{6} } \\ \\ = \frac{ { \cancel{a}^{3}}b }{ \cancel{{a}^{6}} } \\ = {a}^{6 - 3} = {a}^{3} \\ = \frac{b}{ {a}^{3} } [/tex]
Now
[tex] \frac{ {a}^{8} {b}^{6} }{ {b}^{7} {a}^{9} } \\ \\ \frac{ {a}^{8} }{ {a}^{9} } = \frac{1}{a} \\ \\ so \: it \: is \: \frac{ {b}^{6} }{ {b}^{7}a} \\ \\ \frac{ {b}^{6} }{{b}^{7} } = \frac{1}{ba} [/tex]
So now just make a fraction of them by adding + symbol...
So it will be
[tex] \frac{ {b} }{ {a}^{3} } + \frac{1}{ba} \\ \\ [/tex]
I hope it is helpful to you...
Cheers!_____________
a³b⁵ / b⁴a⁶ ÷ a⁸b⁶ / b⁷a⁹ = 1 / a²
Indices:
Indices in math talk about a number raise to another or a variable. They are called exponents.
a³b⁵ / b⁴a⁶ ÷ a⁸b⁶ / b⁷a⁹
Using the law of indices we will simplify the expression as follows;
- a³b⁵ / b⁴a⁶ = a³⁻⁶ / b⁵⁻⁴ = a⁻³ / b = 1 / a³b
- a⁸b⁶ / b⁷a⁹ = a⁸⁻⁹ / b⁶⁻⁷ = a⁻¹ / b⁻¹ = 1 / ab
Therefore, let's combine the individual simplification.
1 / a³b ÷ 1 / ab = 1 / a³b × ab / 1
1 / a³b × ab / 1 = 1 / a²
learn more on simplifying indices here: https://brainly.com/question/10584859?referrer=searchResults
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