stephm51
Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The sum of the angle measures of any triangle is 180°. Find each of the angle measure of a triangle if the second angle measure 10º more than twice the first, and the third angle measures 10° more
than the second.

Sagot :

aayu0302

Answer:

26,72,82

Step-by-step explanation:

This question is solved by a system of equations. We have that:

x is the first angle.

y is the second angle.

z is the third angle.

The sum of the measures of the angles of a triangle is 180.

This means that, x + y + z = 180 -> Eq 1

Now,

The second angle measure 10º more than twice the first,

=> y = 2(x + 10) = 2x + 20

The third angle measures 10° more  than the second,

=> z = y + 10 = 2(x + 10) + 10 = 2x + 20 + 10 = 2x + 30

Equation(Substituting values in Eq 1) :-

=> x + (2x + 20) + (2x + 30) = 180

=> x + 2x + 20 + 2x + 30 = 180

=> x + 2x + 2x + 20 + 30 = 180

=> 5x + 50 = 180

=> 5x = 130

=> x = 26

Therefore,

x = 26

y = 2(26) + 20 = 72

z = 2(26) + 30 = 82

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.